How to Find Direction of Torque on Current Loop

Just so how do you find the direction of torque in a magnetic field. Its direction can be found from another right-hand rule.

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Flemings right hand thumb rule is used to find out the direction of torque on a current loop.

. Since the equation for torque on a current-carrying loop is τ NIAB sin θ the units of N. Where the area vector is perpendicular to the plane of the loop. Mathematically Here A is a vector quantity with the magnitude equal to the area of the rectangular loop and the direction.

The loop has dimensions a 4 cm and b 5 cm. So I suppose many comforts of modern life depend on this interaction. τ τ μ μ B.

-Fa on x-axis -Fb on y-axis -Fa on z-axis -Fb on z-axis For the X-axis I found that torque is 1064e-5 and Fb0 For the y-axis I found the torque is 1064e-5 and Fa0. The direction of Ais perpendicular to the loop in the direction given by the loop RHR. The magnetic moment of a current loop can be defined as the product of the current flowing in the loop and the area of the rectangular loop.

Curl your ngers around with the. Torque on the loop can be found using τ N I ABsinθ τ N I A B sin θ. How To Find the Torque on a Current Loop in a Magnetic Field 1.

Your thumb when you stick it out gives the direction of the area vector. The magnitude of the torque can be given by Torque On Current Loop The Magnetic moment. If you consider an electron in the upper part of the loop then we know the velocity direction of this electron and also the magnetic field at the location of the electron.

The torque on the loop and potential energy are calculated from identifying the magnetic moment magnetic field and angle oriented in the field. In terms of the magnetic dipole moment the torque on a current loop due to a uniform magnetic field can be written simply as τ τ μμ B. The current in side 3 flows in the opposite direction to that of side 1 so.

This physics video tutorial explains how to calculate the torque on a current loop in a uniform magnetic field as well as the magnetic dipole moment. Solution For sin θ 1 the maximum torque is τ max N I AB τ max N I A B Entering known values yields τ max 100150 A0100 m2200 T 300 Nm τ max 100 150 A 0100 m 2 200 T 300 N m. Curl your fingers around with the current and your thumb points in the direction of µ.

Open your palms facing it upward and curl your fingers stick out your thumb facing the current and you can find out the movement of. Its direction can be found from another right-hand rule. This equation holds for a current loop in a two-dimensional plane of arbitrary shape.

If the loop starts from rest in Figure 1920a it will begin to rotate. Curl the fingers on your right hand in the direction of the current flow. 11613 μ I A 20 10 3 A π 002 m 2 25 10 6 A m 2.

Torque causes an object to spin around a fixed axis. What is the direction of the torque on the loop. To find the net force on the loop we have to apply this equation to each of the four sides.

I need to find the. The force on side 1 is F 1 I a B sin 90 θ i I a B cos θ i 1114 where the direction has been determined with the RHR-1. Curl the fingers on your right hand in the direction of the current and your thumb stuck out points in.

In general the torque is given by. Maximum torque occurs when θ 90º and sin θ 1. Consider a uniform magnetic field of strength 38 10-4 T in x y or z directions.

The direction of A is perpendicular to the loop in the direction given by the loop RHR. The angles specified in Figure 1920 are the angles between the area vector and the magnetic field. First nd the magnetic dipole moment of the loop.

Calculate the magnetic field strength needed on a 200-turn square loop 200 cm on a side to create a maximum torque of 300 N m if the loop is carrying 250 A. One can find the movement of the torque by the usage of the formula. Solution The magnetic moment μ is calculated by the current times the area of the loop or π r 2.

This is IA where Iis the current and the magnitude of Ais the area Aenclosed by the loop. The torque on the dipole is τ µB where B is the external magnetic field. Curl the fingers on your right hand in the direction of the current and your thumb stuck out points in the direction of the area vector.

The Lorentz force is given by mathbfF q mathbfvtimes mathbfB and indicates in which directions the charged particles electrons here which have negative q are pushed.

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